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5n^2-31n-28=0
a = 5; b = -31; c = -28;
Δ = b2-4ac
Δ = -312-4·5·(-28)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-39}{2*5}=\frac{-8}{10} =-4/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+39}{2*5}=\frac{70}{10} =7 $
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